Question

( 2/3 x^2 - 1/2 y )^3

Answer 1

( 2/3 x^2 - 1/2 y )^3
\(\dfrac{8}{27}x^6-3.\dfrac{4}{9}x^4.\dfrac{1}{2}y+3.\dfrac{2}{3}x^2.\dfrac{1}{4}y^2-\dfrac{1}{8}y^3\)
\(\dfrac{8}{27}x^6-\dfrac{2}{3}x^4y+\dfrac{1}{2}x^2y^2-\dfrac{1}{8}y^3\)
 

Answer 2

\(\left(\dfrac{2}{3}x^2-\dfrac{1}{2}y\right)^3=\dfrac{8}{27}x^6-\dfrac{2}{3}x^4y+\dfrac{1}{2}x^2y^2-\dfrac{1}{8}y^3\)