\(\dfrac{2}{3}3^x-7.3^x=-405\)
\(\dfrac{2}{3}.3.3^x-7.3^x=-405\)
\(3^x\left(2-7\right)=-405\)
\(3^x.\left(-5\right)=-405\)
\(3^x=81\)
\(3^x=3^4\)
\(x=4\)
Tìm x:
( x.1) + (x.2) + (x.3) +....+ (x.9 ) = 405
tìm x:
3x+2+3x+1+34=405
4 x [ X -12 ] = 2 x X + 164
1\(\frac{1}{4}\)x X - \(\frac{3}{5}\)= \(\frac{4}{5}\)x X + 35%
1/ 3 x 5 + 1/5x9 + ... + 1/401 x 405 + X = 2\(\frac{1}{405}\)
Mọi người giúp mình bài tìm x
1) (x-2/9)^3 = (8/27)^2
2)2.3^x -405 = 3^x-1
3)4/3 : 0,8 = 0,75x : (-1,5)
5x - 2 .(x-1)=-4.3.125.(-25).8
7x + 6 .(3-x)=27 - 20 + 73
6x - 5 . ( x- 7 ) = ( 27 - 514 ) - ( 486 - 73 )
3./x+4/-2.(x-1)= 7-2x
2./x-6/+7x-2=/x-6/+ 7x
//=giá trị tuyệt đối
2,3^x=405=3^x-1
TÌM x:
96-3.(x+1)
405:(5.x-15)
3^x=234
3^x=4096
6^x=216
5.3^x=405
2^x=4
x^5=32
x^2;8=25
X^4=81
5^x^-1+125
5^x^+3=81
(x-2)^5=243
(x-1)^4=16
(x+1)^3=125
(x-2)^3=64
(x-1)^5=32
tìm x:1-2+3-4+...+53-54+x=-73
