Các câu hỏi tương tự
15 tháng 1 2022 lúc 15:22
C = \(\dfrac{3}{1^2.2^2}\) + \(\dfrac{5}{2^2.3^2}\)+\(\dfrac{7}{3^2.4^2}\) +...+ \(\dfrac{19}{9^2.10^2}\)
cmr: 3/1^2.2^2 +5/2^2.3^2 +7/3^2.4^2+.....+19/9^2.10^2 <1
so sánh 2 tổng sau :
A= 2.1+ 2.3+2.5+........+2. 97+ 2.99
B= 2.2+2.4+2.6+........+2.98 +2.100
cho A =\(\dfrac{3}{1^2.2^2}+\dfrac{5}{2^2.3^2}+\dfrac{7}{3^2.4^2}+...+\dfrac{19}{9^2.10^2}\) so sánh A với 1
Tìm x, biết :
\(\left(9!-8!\right).7!.x=1^2.2^2.3^2.4^2.....8^2\)
Giải được thì tick ^^
chứng minh rằng : \(\frac{3}{1^2.2^2}+\frac{5}{2^2.3^2}+\frac{7}{3^2.4^2}+....+\frac{19}{9^2.10^2}< 1\)
CMR\(\frac{3}{1^2.2^2}+\frac{5}{2^2.3^2}+\frac{7}{3^2.4^2}+....+\frac{19}{9^2.10^2}<1\)
CMR\(\frac{3}{1^2.2^2}+\frac{5}{2^2.3^2}+\frac{7}{3^2.4^2}+...+\frac{19}{9^2.10^2}<1\)
Bài 1: Tính : D =\(\frac{3}{1^2.2^2}+\frac{5}{2^2.3^2}+\frac{7}{3^2.4^2}+...+\frac{19}{9^2.10^2}\)