\(\frac{2^{20}.9^3+15.4^9.81^2}{6^8.2^{11}+12^{10}}\)
\(=\frac{2^{20}.3^6+5.2^{18}.3^9}{2^{19}.3^8+2^{20}.3^{10}}\)
\(=\frac{2^{18}.3^6.\left(2^2+5.3^3\right)}{2^{19}.3^8.\left(1+2.3^2\right)}=\frac{139}{2.3^2.19}=\frac{139}{342}\)
CÔNG CHÚA ORI bạn có thể ghi bước trung gian đoạn cuối giúp mk đc ko??? Mk ko hỉu cho lắm
\(\frac{2^{20}.9^3+15.4^9.81^2}{6^8.2^{11}+12^{10}}\)
\(=\frac{2^{20}.3^6+3.5.2^{18}.3^8}{2^8.3^8.2^{11}+4^{10}.3^{10}}\)
\(=\frac{2^{20}.3^6+2^{18}.3^9.5}{2^{19}.3^8+2^{20}.3^{10}}\)
\(=\frac{2^{18}.3^6\left(2^2+3^3.5\right)}{2^{19}.3^8\left(1+2.3^2\right)}\)
\(=\frac{4+27.5}{2.3^2\left(1+18\right)}\)
\(=\frac{4+135}{18.19}\)
\(=\frac{139}{342}\)
