\(\Rightarrow11^x=11^3:\left(125-2^2\right)\\ \Rightarrow11^x=11^3:121=11^3:11^2=11^1\\ \Rightarrow x=1\)
\(\Rightarrow11^x=11^3:\left(125-2^2\right)\\ \Rightarrow11^x=11^3:121=11^3:11^2=11^1\\ \Rightarrow x=1\)
Tìm x:
\(\left(x^2-1\right)^2=9\)
\(12:\left\{390:\left[5.10^2-\left(5^3+x.7^2\right)\right]\right\}=4\)
\(5^3.\left(3x+2\right):13=10^3:\left(13^5:13^4\right)\)
Giúp mik vs nha m.n!>.<
Tìm \(x\)
a) \(\left|x+\frac{1}{2}\right|=\frac{1}{3}\)
b) \(\left|x-\frac{1}{2}\right|=\frac{1}{3}-\frac{1}{2}\)
c) \(\left|x+\frac{1}{3}\right|-4=-1\)
d) \(\left|x-\frac{1}{5}\right|+\frac{1}{3}=\frac{1}{4}-\left|\frac{-3}{2}\right|\)
e) \(\left|x-\frac{5}{2}\right|=\frac{4}{3}-\left(\frac{2}{3}-\frac{1}{2}\right)\)
giúp mik vs ạ mik đag cần rất gấp!
mn ơi giúp mik vs!!!
Rút gọn p. số:
\(\dfrac{2.\left(-13\right).9.10}{\left(-3\right).4.\left(-5\right).26}\)
Nhờ mn giúp mik với ạ
Tìm GTNN
A= \(\left(x-3y\right)^2+\left(2x-1\right)^4\)
B= \(\left|x-2\right|+\left|3x-2y\right|-4\)
C= \(\dfrac{-4}{\left|x+1\right|\left|y-3\right|+2}\)
D=\(\left|x-5\right|+\left|x-1\right|+7\)
a, \(x-\left[\frac{17}{2}-\left(\frac{-3}{7}+\frac{5}{3}\right)\right]=\frac{-1}{3}\)
b,\(\frac{9}{2}-\left[\frac{2}{3}-\left(x-\frac{7}{4}\right)\right]=\frac{-5}{4}\)
giúp mik với nhé !!! bài khó mik ko làm đc
tìm x biết
\(\dfrac{7}{9}:\left(2+\dfrac{3}{4}.x\right)+\dfrac{5}{9}=\dfrac{23}{27}\)
|x|\(-\dfrac{3}{4}=\dfrac{5}{3}\)
\(\left|2.x-\dfrac{1}{3}\right|+\dfrac{5}{6}=1\)
giúp mk vs nhanh lên mình đang bận
\(3\left(x-\frac{1}{5}\right)-7\left(\frac{5}{14}-3\right)=20\)
\(\frac{2}{3}-\frac{1}{5}\left(x-\frac{1}{4}\right)=\frac{3}{2}-\frac{1}{4}\)
Giúp mình vs !!!!!!!@@@@@
Thanks trước nha
Tìm x biết
a) \(11-\left(3x-1\right)=\frac{9}{2}-\left(5-3,5x\right)\)
b)\(-1\le\frac{2x}{3}<3\frac{1}{2}\) vầ x thuộc Z
c)\(2\left(x+\frac{1}{2}\right)-\frac{x}{3}=1\frac{1}{2}:\left(-0,25\right)\)
Giải giúp mình nhé
giúp mik vs mai mik phải nộp rồi
Giair giúp mik nha,cảm ơn các bạn nhìu.
Tính giá trị của các biểu thức sau:
\(C=\left(1+\frac{2}{3}\right).\left(1+\frac{2}{5}\right).\left(1+\frac{2}{7}\right)........\left(1+\frac{2}{2013}\right).\left(1+\frac{2}{2015}\right)\)
\(N=\frac{5.\left(2^2.3^2\right)^9.\left(2^2\right)^6-2.\left(2^2.3\right)^{14}.3^6}{5.2^{28}3^{19}-7.2^{29}.3^{18}}\)