triệu hồi lá bài 'Quang Nhân ' ( Maximilian ) :)))
\(2011-\left(5.5^2-\left(7^3:7+1\right)\right)\)
\(2011-\left(125-50\right)\)=1936
\(2011-\left\{5.5^2-\left[\left(7^3:7\right)+1\right]\right\}\)
\(=2011-\left\{5^3-\left[7^2+1\right]\right\}\)
\(=2011-\left\{125-\left[49+1\right]\right\}\)
\(=2011-\left\{125-50\right\}\)
\(=2011-75\)
\(=1936\)