Tính giá trị các biểu thức sau và viết kết quả dưới dạng bình phương của 1 số
A = 2^5 x (-5)^2 - 8^2 - 7
B = 2^3 x (-4)^2 + (-3)^2 x 3^2 - 40
C= (1/4 - 1/2 - 1) ^3 x (2 - 2/5)^3
D = ( -1/4)^2 : (1/2 - 1/3)
E= 4 x (1/4)^2 + 25 x [(3/4)^3 : (5/4)^3] : (3/2)^3
F = 2^3 + 3 x (1/2)^0 - 1+[(-2)^2 : 1/2] - 8
TÌM X, BIẾT:
a) 3 . ( 1/2 - x ) + 1/3 = 7/6 - x
b) 4 . ( 1/2 - x ) - 5 . ( x - 3/10 ) = 7/4
c) -3/2 . ( 4/5 - 2/3 ) + x = 4 . ( x - 1/2 )
d) 2 . ( 3/2 - x ) - 1/3 = 7x - 1/4
e) 1/5 . ( -3/5 -10 ) + 5x = x - 2/3
f) -3/2 . ( 5 - 1/6 ) + 4 . ( x - 1/2 ) = 1
~ PLEASE HELP ME ~
B1:tìm x biết a, (-2+x^2)(x^2-2)(x^2-2)(x^2-2)(x^2-2)=1 b, (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4) c,(8x-3)(3x+2)-(4x+7)(x+4)=(4x+1)(5x-1) d, 2x^2+3(x-1)(x+1)=5x(x+1) e, (8-5x)(x+2)+4(x-2)(x+1)=(2+x)(2-x) f, 4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)
Bài 1:
a, (-2+x\(^2\))(x\(^2\)-2)(x\(^2\)-2)(x\(^2\)-2)(x\(^2\)-2)=1
b, (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4)
c, (8x-3)(3x+2)-(4x+7)(x+4)=(4x+1)(5x-1)
d,2x\(^2\)+3(x-1)(x+1)=5x(x+1)
e,(8-5x)(x+2)+4(x-2)(x+1)=(2+x)(2-x)
f, 4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)
Bài 1. Tìm x, biết:
a/ 1/4.(x-3)+2=1/5
b/ 1/7-2.(x+1)=1/4+2/3
c/ 1/4.(2x+3)-1/9=2/5
d/ 3/2.(x+1)-4/9=2/3
e/ 4/5.(2-3x)+4/7=2và1/3
[Cần gấp ạ!]
1,Tìm x, biết:
a, |x|+1/3=4/5
b, |x+2/3|=1/4
c, |x-3/4|-2/3=3/5
d, 1/4+2.|2/3-x|=3/4
e, 16^x:4^x=16
g, (2x+1)^3=-64
h, 2^x/2+4.2^x=72
2,Tính
A=(1/2-1).(1/3-1).(1/4-1).....(1/2015-1)
B=1/1.2+1/2.3+1/3.4+...+1/2014.2015
tìm x biết
(2/5-x) : 4/3 +1/2 =-4
(-3 +3/x - 1/3 ) : ( 1+ 2/5 2/3 ) = -5/4
-3x/4 .( 1/x +2/7 ) =0
3 - 1-1/2/1+1/x= 5/3
tìm x biết
a).|x|-3/4=4/5
b).|x+1/3|-1/2=1/4
c).3.|2.x-3|+4=9/2
d).|2.x-5|=x-1
e).|3-4.x|=2-x