2/
a)\(\dfrac{1}{5}+\dfrac{4}{5}+\dfrac{4}{11}+\dfrac{7}{11}\)
= \(\dfrac{5}{5}+\dfrac{11}{11}\)
= \(1+1\)
= \(2\)
b) \(\left(\dfrac{1}{8}+\dfrac{3}{8}\right)+\left(\dfrac{4}{12}+\dfrac{5}{12}\right)\)
= \(\dfrac{4}{8}+\dfrac{8}{12}\)
= \(\dfrac{12}{24}+\dfrac{16}{24}\)
= \(\dfrac{28}{24}\)
= \(\dfrac{7}{6}\)