Question

2. tìm x biết 

1/2+3/4x+1/4

5/6+1/6:x=-2

x*(x-2/3)=0

Answer 1

x . ( x - \(\frac{2}{3}\)) = 0

=> x = 0 hoặc x - \(\frac{2}{3}\)= 0

=> x - \(\frac{2}{3}\)= 0

      x           = 0 + \(\frac{2}{3}\)

       x          = \(\frac{2}{3}\)

Vậy, x \(\in\){ 0, \(\frac{2}{3}\)}

~ Chúc học tốt ~

Ai ngang qua xin để lại 1 L - I - K - E

Answer 2

\(\frac{1}{2}+\frac{3}{4}x=\frac{1}{4}\)

\(\Leftrightarrow\frac{3}{4}x=\frac{1}{4}-\frac{1}{2}\)

\(\Leftrightarrow\frac{3}{4}x=-\frac{1}{2}\)

   \(\Leftrightarrow x=-\frac{2}{3}\)

      

\(\frac{5}{6}+\frac{1}{6}:x=-2\)

\(\Leftrightarrow\frac{1}{6}:x=-\frac{17}{6}\)

\(\Leftrightarrow x=-\frac{1}{17}\)

     

\(x\cdot\left(x-\frac{2}{3}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x-\frac{2}{3}=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{2}{3}\end{cases}}\)