\(a;\left(x+1\right)\times\left(x+3\right)-x\times\left(x+2\right)=7\)
\(\Leftrightarrow x^2+4x+3-x^2-2x=7\)
\(\Leftrightarrow2x+3=7\Rightarrow x=\frac{7-3}{2}=2\)
Vậy x=2
\(b;2x\left(3x+5\right)-x\left(6x-1\right)=33\)
\(\Leftrightarrow6x^2+10x-6x^2+x=33\)
\(\Leftrightarrow11x=33\Leftrightarrow x=3\)
Vậy x=3
\(\dfrac{1}{2}\) . \(x\) + \(\dfrac{3}{5}\) . (\(x\) - 2) =3
3 - (\(\dfrac{1}{6}\) - \(x\)) . \(\dfrac{2}{3}\) = \(\dfrac{2}{3}\)
Tìm x :
a) ( x^2 +1)^3 - (x^4 - x^2 +1 ) . ( x^2 +1 )=0
b) (x - 3 )^3 - (x - 3 ) . ( x^2 + 6x + 9) + 6 .( x+1)^2 + 6x^2 = 33
3x-21/3 + 4x-32/2 = 5x-37/4 + 9x-33/6
x+5/4 + x+6/3 + x+7/2 + x+8/1 = -4
Tìm x biết :
a, 4.(18 - 5x) - 12.(3x - 7) = 15.(2x - 16) - 6(x + 14)
b, 5.(3x + 5) - 4.(2x - 3) = 5x + 3.(2x + 12) + 1
c, 2.(5x - 8) - 3.(4x - 5) = 4.(3x - 4) + 11
d, (3x + 2)(2x + 9) - (x + 2)(6x + 1) = (x + 1) - (x - 6)
e, (8x - 3)(3x + 2) - (4x + 7)(x + 4)= (2x + 1)(5x - 1) - 33
Tìm x,y
(x+3).(y+2)= 1
(x-1).(x+y)= 33
(2x-5).(y-6)= 17
3x+4y-xy= 16
tính
a/1/2x+3/5x=-33/25 b/(2/3x-4/9)(1/2+(-3/7):x)=0
c/x+5/2005+(x+6/2004)+(x=7/2003)=-3
tìm x biết
1) x=-1/2 + 3/4 2) x - 1/5 = 2/11 3) x - 5/6 = 16/42 + -8/56
4) x/5 = 5/6 + -19/30 5) |x| - 1/4 = 6/18 6)x = -1/2 +3/4
7) x/15 = 3/5 + -2/3 8)11/8 + 13/6 = 85/x 9) x - 7/8 = 13/12
10) x - -6/15 = 4/27 11) -\(\dfrac{-6}{12}\)+ x = 9/48 12) x - 4/6 = 5/25 + -7/15
Bài 1 : Tìm số nguyên x biết :
a. 2^x-2 - 5 = 8
b. |x| -3 = 0
c.|x-1| + 5 = 8
d. 2.|x+1| -1 = 3
Bài 2 : Tìm x
a . 1/7 = 8/-x
b. 3x/9=2/6
c . 4 2/5( hỗn số ) : (-33/10) + x = -1 5/6 ( hỗn số )
d. 0,25.x - 27/8 .x =3/4
e. 5x^2 - 12 =68
1/7=8/-x
3x/9=2/6
4/2/5:(-33/10)+x=-1/5/6
(x-2/1/4):(-5/6)=3
-8:(4/1/5x+3/10)=4/4/9
(5,5x-44):(-3/2)=30
(13/10x-15).(-5/14)=3
1/3.(x+5/2)=-2
chu y dau( //)la so tap phan con dau( /) la phan so
