Question

1/x-2 + 1/y-1=2

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2/x-2 - 3/y-1=1

(Các biểu thức trên ở trong dấu ngoặc nha😝😝😝)

Answer 1

\(\left\{{}\begin{matrix}\dfrac{1}{x-2}+\dfrac{1}{y-1}=2\\\dfrac{2}{x-2}-\dfrac{3}{y-1}=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{3}{x-2}+\dfrac{3}{y-1}=6\\\dfrac{2}{x-2}-\dfrac{3}{y-1}=1\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{5}{x-2}=7\\\dfrac{1}{x-2}+\dfrac{1}{y-1}=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x-2=\dfrac{5}{7}\\\dfrac{1}{y-1}=\dfrac{3}{5}\end{matrix}\right.\)

=>x=19/7; y-1=5/3

=>x=19/7; y=8/3