1)3x4-5x3y+6x2-10xy+2
=(3x4-5x3y)+(6x2-10xy)+2
=x3(3x-5y)+2x(3x-5y)+2
=x3.0+2x.0+2
=0+0+2
=2
2) x5-2010x4+2010x3-2010x2+2010x-2020
=x5-(2009+1)x4+(2009+1)x3-(2009+1)x2+(2009+1)x-2009-11
=x5-(x+1)x4+(x+1)x3-(x+1)x2+(x+1)x-x-11
=x5-x5-x4+x4+x3-x3-x2+x2+x-x-11
=-11
2, Với x= 2009 => 2010=x+1
=> \(x^5-2010\text{x}^4+2010\text{x}^3-2010\text{x}^2+2010\text{x}-2020=x^5-\left(x+1\right)x^4+\left(x+1\right)x^3-\left(x+1\right)x^2+\left(x+1\right)x-2020\)
\(=x^5-x^5-x^4+x^4+x^3-x^3-x^2+x^2+x-2020\)
\(=x-2020\)
\(=2009-2020\\ =-11\)