Question

1.Tìm x,biết

x+(x+1)+(x+2)+(x+3)+...+(x+100)=8080

Answer 1

x+(x+1)+(x+2)+...(x+100)=8080

(x+x+x+..+x)+(0+1+2+...+100)=8080

101x+5050=8080

101x=8080-5050

101x=3030

x=3030:101

x=30

Answer 2

x + ( x + 1 ) + ( x + 2 ) + ( x + 3 ) +.....+ ( x + 100 ) = 8080

=( x + x + x + x +....+ x ) + ( 1 + 2 + 3 + 4 + .... + 100) = 8080

=(x + x + x + ... + x ) + 5050 = 8080

 101x = 8080 - 5050

101x = 3030

x = 3030 : 101

x = 30

Answer 3

=(x + x + x + ... + x ) + 5050 = 8080

 101x = 8080 - 5050

101x = 3030

x = 3030 : 101

x = 30