Ta có: |x - 2019| ≥ 0 => |x - 2019|2019 ≥ 0
|x - 2020| ≥ 0 => |x - 2020|2020 ≥ 0
+) TH1: \(\hept{\begin{cases}\left|x-2019\right|^{2019}=0\\\left|x-2020\right|^{2020}=1\end{cases}\Rightarrow}\hept{\begin{cases}\left|x-2019\right|=0\\\left|x-2020\right|=1\end{cases}}\Rightarrow\hept{\begin{cases}x-2019=0\\\left|x-2020\right|=1\end{cases}\Rightarrow}\hept{\begin{cases}x=2019\\\left|x-2020\right|=1\end{cases}}\)
Giải: |x - 2020| = 1
TH1: x - 2020 = 1 => x = 2021
TH2: x - 2020 = -1 => x = 2019
Vì 2021 ≠ 2019
=> x = 2019
+) TH2: \(\hept{\begin{cases}\left|x-2019\right|^{2019}=1\\\left|x-2020\right|^{2020}=0\end{cases}\Rightarrow}\hept{\begin{cases}\left|x-2019\right|=1\\\left|x-2020\right|=0\end{cases}}\Rightarrow\hept{\begin{cases}\left|x-2019\right|=1\\x-2020=0\end{cases}\Rightarrow}\hept{\begin{cases}\left|x-2019\right|=1\\x=2020\end{cases}}\)
Giải |x - 2019| = 1
Th1: x - 2019 = 1 => x = 2020
Th2: x - 2019 = -1 => x = 2018
Vì 2018 ≠ 2020
=> x = 2020
Vậy x \(\in\){ 2020; 2019 }
P/s: Ko chắc :)
Trả lời :
Bạn Kan làm đúng rồi nha !
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#Sơn%#
Trả lời
Bạn làm theo bài bạn Kan nha
bạn ý làm đúng rồi
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