\(\dfrac{x}{x+1}=\dfrac{x+1-1}{x+1}=1-\dfrac{1}{x+1}\)
\(\dfrac{x+1}{x+2}=\dfrac{x+2-1}{x+2}=1-\dfrac{1}{x+2}\)
x+1<x+2
=>1/x+1>1/x+2
=>-1/x+1<-1/x+2
=>x/x+1<x+1/x+2
x x + 1 = x + 1 − 1 x + 1 = 1 − 1 x + 1 x + 1 x + 2 = x + 2 − 1 x + 2 = 1 − 1 x + 2 x+11/x+1>1/x+2 =>-1/x+1<-1/x+2 =>x/x+1