Question

1/9 . 3^5 . 3^x = 3^2x+1

Answer 1

\(\dfrac{1}{9}.3^5.3^x=3^{2x+1}\\ \Rightarrow3^{5+x}:9=3^{2x+1}\\ \Rightarrow3^{5+x}:3^2=3^{2x+1}\\ \Rightarrow3^{5+x-2}=3^{2x+1}\\ \Rightarrow3^{x+3}=3^{2x+1}\\ \Rightarrow x+3=2x+1\\ \Rightarrow2x+1-x-3=0\\ \Rightarrow x-2=0\\ \Rightarrow x=2\)