d.\(2^3.15-[115+\left(12-25\right)]\)
120-102=18
(-17)+14+(-12)
=[(-17)+14]+(-12)
=(-3)+(-12)
=-15
a, 5^10 : 5^8 + 60 : 12 + (-10)
= 5^2 + 60 : 12 - 10
= 25 + 5 -10
= 30 - 10
= 20.
2 mũ 3 .15 – [ 115 + ( 12 - 25)]
=\(2^3\).15-(115+13)
=\(2^3\).15-128
=8.15-128
=120-128
=(-8 )hoặc(+8)