Question

16x^2 - 8x + 1

 

Answer 1

`16x^2-8x+1`

`=(4x)^2-2.4x+1`

`=(4x-1)^2`

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`=>(4x-1)^2>=0`

Dấu "=" `<=>4x-1=0<=>x=1/4`

Answer 2

\(16x^2-8x+1\)=0

\(16x^2-4x-4x+1=0\)

\(\left(16x^2-4x\right)-\left(4x-1\right)=0\)

\(4x\left(4x-1\right)-\left(4x-1\right)=0\)

\(4x-1=0\)

4x=1

x= \(\dfrac{1}{4}\)

Answer 3

     16x² - 8x + 1 = 0

△' = 4² - 16

△' = 16 - 16

△' = 0

=> phương trình có nghiệm kép: x1 = x2 = 1/4

Answer 4

\(16x^2-8x+1\)

\(=\left(4x\right)^2+2.4x.1+1^2\)

\(=\left(4x+1\right)^2\)

Hằng đẳng thức: \(\left(A+B\right)^2=A^2+2AB+B^2\)