Lời giải:
$15x^2-65x+110=-10$
$\Leftrightarrow 15x^2-65x+120=0$
$\Leftrightarrow 3x^2-13x+24=0$
$\Leftrightarrow 3(x^2-\frac{13}{3}x+\frac{13^2}{6^2})+\frac{119}{12}=0$
$\Leftrightarrow 3(x-\frac{13}{6})^2+\frac{119}{12}=0$
$\Leftrightarrow 3(x-\frac{13}{6})^2=-\frac{119}{12}<0$ (vô lý)
Vậy pt vô nghiệm/.