\(\dfrac{15}{23}.\left(x-\dfrac{3}{8}\right)=\dfrac{25}{46}\)
\(x-\dfrac{3}{8}=\dfrac{25}{46}:\dfrac{15}{23}\)
\(x-\dfrac{3}{8}=\dfrac{25}{46}.\dfrac{23}{15}\)
\(x-\dfrac{3}{8}=\dfrac{5}{2}.\dfrac{1}{3}\)
\(x-\dfrac{3}{8}=\dfrac{5}{6}\)
\(x\) \(=\) \(\dfrac{5}{6}+\dfrac{3}{8}\)
\(x\) \(=\dfrac{20}{24}+\dfrac{9}{24}\)
\(x\) \(=\dfrac{29}{24}\)
Vậy \(x=\dfrac{29}{24}\)