\(\dfrac{1}{5}\left(-\dfrac{3}{5}-10\right)+5x=x-\dfrac{2}{3}\)
=>\(4x=-\dfrac{2}{3}-\dfrac{1}{5}\left(-\dfrac{3}{5}-10\right)\)
=>\(4x=-\dfrac{2}{3}+\dfrac{3}{25}+2=\dfrac{109}{75}\)
=>\(x=\dfrac{109}{75}:4=\dfrac{109}{300}\)
\(\dfrac{1}{5}\left(-\dfrac{3}{5}-10\right)+5x=x-\dfrac{2}{3}\)
=>\(4x=-\dfrac{2}{3}-\dfrac{1}{5}\left(-\dfrac{3}{5}-10\right)\)
=>\(4x=-\dfrac{2}{3}+\dfrac{3}{25}+2=\dfrac{109}{75}\)
=>\(x=\dfrac{109}{75}:4=\dfrac{109}{300}\)
1 tìm x
A. 3x-3/2-5x+10/3=1
B.- 1/5x 02/3=1/10 x +5/6
C.3/2(x-5/3)-4/5=x+1
Ai giúp mk vs.Mk đang gấp
1 tìm x
A. 3x-3/2-5x+10/3=1
B.- 1/5x 02/3=1/10 x +5/6
C.3/2(x-5/3)-4/5=x+1
Ai giúp mk vs.Mk đang gấp
-(x/2) + 2x/3 + (x+1)/4 + (2x+1)/6 = 3/8
3/(2x+1) + 10/(4x+2) - 6/(6x+3)=12/26
5/1x6 + 5/ 6x11 + ... +5/(5x+1)(5x+6)=2005/2006
-(x/2) + 2x/3 + (x+1)/4 + (2x+1)/6 = 3/8
3/(2x+1) + 10/(4x+2) - 6/(6x+3)=12/26
5/1x6 + 5/ 6x11 + ... +5/(5x+1)(5x+6)=2005/2006
Tìm x
a) 5^x -1 = 5^2 + 100
b) x^10=x
2 x 5^2 x 3^2 + {[2 x 5^3 - (5x + 4) x 5 : (2^3 x 3 x 5)]}=455
1)5x+2(x+1/2)=7
2)8x-3(x+2)=9
3)5(x-2)+3(x-1)=19
4)7(x-3)-2x-5=11
5)6x+3-2(x-5)=30
6)8(x-1/8)-5(x-1/5)=10
7)13x-5-2(x+3)=1
8)4(x-2)-2(x-1)=12
9)6x-13-2-(x×5)=7
10)7(x-5)-3(x+5)=30
-(x/2) + 2x/3 + (x+1)/4 + (2x+1)/6 = 3/8
3/(2x+1) + 10/(4x+2) - 6/(6x+3)=12/26
5/1x6 + 5/ 6x11 + ... +5/(5x+1)(5x+6)=2005/2006
Giải thích hộ :v
Tìm x, biết:
a) 5.2²+(x+3)=5²
b)2³+(x-3²)=5³-4³
c)4.(x-5)-2³=2⁴.3
d)5.(x+7)-10=2³.5
e)7²-7.(13-x)=14
f)5x-5²=10
g)9x-2.3²=3⁴
h)10x+2².5=10²
i)125-5.(4+x)=15
j)2⁶+(5+x)=3⁴
x(x+1/2)-1/5x-1/10 / 3 . x(x-1/2)-1/3x+1/6 / 5
x(x+1/2)-1/5x-1/10 / 3 . x(x-1/2)-1/3x+1/6 / 5