Ta có: \(\left(14-3x\right)^2=25\)
=>\(\left(3x-14\right)^2=25\)
=>\(\left[\begin{array}{l}3x-14=5\\ 3x-14=-5\end{array}\right.\Rightarrow\left[\begin{array}{l}3x=19\\ 3x=9\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac{19}{3}\\ x=3\end{array}\right.\)
\(\left(3x-1\right)^3=25.\left(3x-1\right)\)
\(\left(3x-14\right)^3=2^5.5^2+200\)
-2x+15 < 3x - 17 < 19 -x
x+(x+1) + (x+2) + (x+3) + ... +13 +14 = 14
25 + 24 + 23 + ... + x + (x-2) + (x-3) = 25
1)14 - 3x = -x + 4
2) 2(x-2) + 7 = x-25
1,TÌM SỐ NGUYÊN X BIẾT
H, 3X +12= 2X-4
I, 14 -3X= -X+4
K,2(X-2)+7= X-25
Tìm x
25-{14-[(2-x)-(x+13)+23]} = 62-{8-[(2x-10)-(29-3x)+8]}
bài1
a)21-2(x+6)=15
b)3^x+1=27
c)14-x=36
d)-3x+25=-2
e)37-2(x+6)=29
h)2^x-1=16
tìm x
17x – ( -16x – 37) = 2x +
-2x –3. (x – 17) = 34 – 2(-x + 25
17x + 3. ( -16x – 37) = 2x + 43 - 4x
103 -57: [-2. (2x – 1)2 – (-9)0] = -106
3x – 32 > -5x + 1
15 + 4x < 2x – 145
-3. (2x + 5) -16 < -4. (3 – 2x)
-2x + 15 < 3x – 7 < 19 – x
x + (x+1) + (x+2) + (x+3) + .... + 13 + 14 = 14
25 + 24 + 23 +...+ x + (x - 2) + (x – 3) = 25
a) 3x + 2 . (-7) = 10
b) 25 -(30 + x) = - (27 - 8)
c) 15 - x = 12 - ( -14)
d) (4x + 11) - ( x + 34) = 67
e) 3 - 17 - x = 289 - (36 + 289)
