\(1+3+5+...+x=36\\\left[ \left(x-1\right):2+1\right]\cdot\left(x+1\right):2=36\\ \dfrac{x-1+2}{2}\cdot\dfrac{x+1}{2}=36\\ \dfrac{x+1}{2}\cdot\dfrac{x+1}{2}=36\\ \dfrac{\left(x+1\right)^2}{4}=36\\ \left(x+1\right)^2=36\cdot4=144\)
TH1: x + 1 = 12 => x = 11
TH2: x + 1 = -12 => x = -13
Vì: x phải lớn hơn 0 => x = 11
chứng minh B = 36 / 1 x 3 x 5 + 36 / 3 x 5 x7 + 36 / 5 x 7 x 9 + .... + 36 / 25 x 27 x29 < 3
Tim x la phan tu cua N biet
a ) ( x - 5 ) x 4 = 36
b) ( 48 - x ) x 2 = 14
c) ( 2 x X - 3 ) x 5 = 4
d) 1 + 3 + 5 +..........+ X = 36
e) 1 + 2 + 3 + ...........+ X = 55 + 6 +.....+ 2X = 110
Tìm x, biết: a) x = 1/4 + 5/13 b) x/3 = 2/3 + -1/7 c) x/3 = 16/24 + 24/ 36
d) x/15 = 1/5 + 2/3
a)x-1/9=8/3
b)x/5=5/6+-13/30
c)3/4+1/4:x=-1
d)1/4-5/18<x/36<-8/5+1(x(-z)
giúp mik với
1. Tìm số tự nhiên x biết
a. 37-7.(x+1)=40-8.3
b. (x+5).3+11=10+(3+4).4
c. 25-5.3+4.10=100-5.x
d. 36+2.(x-7)=12+8.(3+5)-36
e. 3.(x+7)-9=11.5-5-8
(ai biết giúp mình, mình tick cho nhé)
tim x : 1+3+5+...+x = 36
1+3+5+...+x=36. Tìm x
Tìm x biết 1+3+5+...+x=36
a)2/x=y/3
b)5/15=1/x=y/21=10/z
c)-36/6=6/x=-9/y^2=z^3/36
1+3+5+...+x=36
