Theo bài ra , ta có :
(1+3+5+7+..........+2007).(125125.127-127127.125)
= (1+3+5+7+..........+2007) . (125 . 1001 . 127 - 127.1001.125)
= (1+3+5+7+..........+2007) . 0
= 0
Đáp số : 0
(1+3+5+7+..........+2007).(125125.127-127127.125)
= (1+3+5+7+..........+2007) . (125 . 1001 . 127 - 127.1001.125)
= (1+3+5+7+..........+2007) . 0
= 0
ta có: 125125.127-127127.125=0
suy ra biểu thức trên bằng 0
\(A=\left(1+3+5+...+2017\right)\cdot\left(125125\cdot127-127127\cdot125\right)\)
\(=\left(1+3+5+7+...+2017\right)\cdot\left(125\cdot1001\cdot127-127\cdot1001\cdot125\right)=0\)
