\(A=\dfrac{1}{3}\left(1+\dfrac{1}{2}+...+\dfrac{1}{256}+\dfrac{1}{512}\right)\)
Đặt B=1+1/2+...+1/256+1/512
=>2B=2+1+...+1/128+1/256
=>B=2-1/512=1023/512
=>\(A=\dfrac{1}{3}\cdot\dfrac{1023}{512}=\dfrac{341}{512}\)
1/3+1/6+1/12+1/24+....+1/768+1/1536
Tính nhanh 3+6+12+24+.....+1536
1- 1/3 - 1/6 - 1/12 - 1/24
2-7/9-5/6 và 1-1/3-1/6-1/12-1/24
1/3+1/6+1/12+1/24+1/48+1/96
1/3 + 1/6 + 1/12 + 1/24 + 1/48 + 1/96 + 1/192 + 1/384 =
2/5+2/3+3/4
2/6+3/12
5/6+1/3
1/3+5/12+5/6
5/8+4/7
1/5+5/35
5/8+3/4
1/6+1/3+1/12
1/6+5/24+2/3
7/3+8/7
2/5+1/6
1/7+1/4+6/7+3/4
giúp với
và ai giải được gọi cụ
Tính:
1 - 1/3 - 1/6 - 1/12 - 1/24 = .........................................................
A=1/3+1/6+1/12+1/24+1/48+1/96+1/192
