Ta có: \(\dfrac{1}{2}x-\dfrac{3}{5}x=3\)
nên \(\dfrac{-1}{10}x=3\)
hay x=-30
Ta có: \(\dfrac{1}{2}x-\dfrac{3}{5}x=3\)
nên \(\dfrac{-1}{10}x=3\)
hay x=-30
cíu tui zới
tui hứa sẽ tick
3) 2x + 3 + 2x = 36
4) 4x+1 - 22x = 12
5) 5x+3 - 5x+1= 3000
4) 4x+1 - 22x
1/ 3(x - 1) - 5(x - 2) = 4(x + 1)
2/ -2(x - 2) - 4(x + 1) = -3(x + 3)
3/ 3x\(^2\) + 2x = 0
4/ x\(^2\) - 5x = 0
5/ (2x - 3)\(^2\) = 36
6/ (5x - 1)\(^3\) = 125
7/ 3\(^x\) + 1 = 27
-(x/2) + 2x/3 + (x+1)/4 + (2x+1)/6 = 3/8
3/(2x+1) + 10/(4x+2) - 6/(6x+3)=12/26
5/1x6 + 5/ 6x11 + ... +5/(5x+1)(5x+6)=2005/2006
-(x/2) + 2x/3 + (x+1)/4 + (2x+1)/6 = 3/8
3/(2x+1) + 10/(4x+2) - 6/(6x+3)=12/26
5/1x6 + 5/ 6x11 + ... +5/(5x+1)(5x+6)=2005/2006
-(x/2) + 2x/3 + (x+1)/4 + (2x+1)/6 = 3/8
3/(2x+1) + 10/(4x+2) - 6/(6x+3)=12/26
5/1x6 + 5/ 6x11 + ... +5/(5x+1)(5x+6)=2005/2006
Giải thích hộ :v
tim x:(2x-1-5x):(3-4x-7)=-2(3-2x-1)
Tìm x biết:
a)\(\text{/5x+2/+/3+5x/=1}\)
b)\(/3x+2/+/1-5x/=3-2x\)
c)\(/x+1/+/x+2/+3-2x=6\)
Tìm x biết a 3 2x 95b 9 . 5 x 3 6.56 3 . 56c 5x 4 3 . 5x 3 511 . 2d 3x 2 4 . 3x 1 1 . 36e 5x 3 105.6344.33 Giups mk vs nhé các cậu .
(5x-1)-(2x-3)=-7+2x