\(\left(\dfrac{1}{4}x-5\right).\left(\dfrac{1}{4}x+5\right)\)
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Bài 3: Những hằng đẳng thức đáng nhớ
Các câu hỏi tương tự
Rút gọn :
1. (2x-5)(3x+1)-(x-3)^2+(2x+5)^2-(3x+1)^3
2. (2x-1)(2x+1)-3x-2)(2x+3)-(x-1)^3+(2x+3)^3
3. (x-2)(x^2+2x+4)-(3x-2)^3+(3x-4)^2
4. (7x-1)(8x+2)-(2x-7)^2-(x-4)^3-(3x+1)^3
5. (5x-1)(5x+1)-(x+3)(x^2-3x+9)-(2x+4)^2-(3x-4)^2+(2x-5)^3
6. (4x-1)(x+2)-(2x+5)^2-(3x-7)^2+(2x+3)^3=(3x-1)^3
Bài 1: Khai triển hằng đẳng thức:
a, ( x - y + 2z )2
b, ( 2x-3 ). ( 2x+3 ) . ( 4x2+9 )
Bài 2: Rút gọn biểu thức:
a, ( 5x+2 ).( 2-5x ) - ( 3x+2 ).( 2x+5 )2
b, ( -2x-3 )2 + 2(2x+1).( 2x+5 ) + ( 2x+5 )2
Tìm x: a)(2x+1)(1-2x)+(1-2x)^2=18
b) 2(x+1)^2-(x-3)(x+3)-(x-4)^2=0
c) (x-5)^2-x(x-4)=9
d) (x-5)^2+(x-4)(1-x)=0
(2x-1)^2-(x-3)(2x+5)
x(2x-5)-3(3x-1)^2.x-3x
(3x-1)^3-(2x-1)(4x^2+4x+1)
(1+3x)(1-3x+9x^2)-(2x-1)^3
2(x-3)(x+3)-x(2x-1)(x-3)
ai giúp mình với khó quá:<
a) A=(2x-5)\(^2\)-(2x=5)\(^2\)+40x-1
Tìm x biết
1.(x+3)2-(x+2).(x-2)=4x+17
2.(2x+1)2-(4x-1).(x-3)-15=0
3.(2x+3).(x-1)+(2x-3).(1-x)=0
4.2(5x-8)-3(4x-5)=4(3x-4)+11
5.(3x-1).(2x-7)-(1-3x).(6x-5)=0
1.(x+2)3+(x-3)2-x2(x+5)
2.(2x+3).(x-5)+2x(3-x)+x-10
3.(x+5).(x2-5x+25)-x(x-4)2+16x
4.(-x-2)3+(2x-4).(x2+2x+4)-x2.(x-6)
1.(x+2)3+(x-3)2-x2(x+5)
2.(2x+3).(x-5)+2x(3-x)+x-10
3.(-x-2)3+(2x-4).(x2+2x+4)-x2.(x-6)
Rút gọn biểu thức:
a) (2x+5)2+(2x-5)2-(2x-1)(2x+1)
b) (2a+b)3+(2a-b)3-16a3
c) (2x-1)3-(x-2)(x2+2x+4)-7x3-2x
d) (x+1)2-(x-1)2-3(x+1)(x-1)
e) (x2+2)2-(x-2)(x+2)(x2+4)
1. khai triển HĐT :
(3x+4)^2=
(x-1)^2=
(x-3)^2=
(1/2x-5)^2 =
x^2-1=
x^2-y^2 =
x^2-2=
4x-1/9 =
3. viết cac biểu thức sau dươi dang HĐT
x^2 -2x+1
x^2 -10x +25
x^2+x +1/4
(2x-3) (2x+3)
(2/3x+5) (2/3x-5)