Bài 1:
\(\left(3x+4\right)^2=9x^2+24x+16\)
\(\left(x-1\right)^2=x^2-2x+1\)
\(\left(x-3\right)^2=x^2-6x+9\)
\(\left(\dfrac{1}{2}x-5\right)^2=\dfrac{1}{4}x^2-5x+25\)
\(x^2-1=\left(x+1\right)\left(x-1\right)\)
\(x^2-y^2=\left(x+y\right)\left(x-y\right)\)
\(x^2-2=\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)\)
\(4x-\dfrac{1}{9}=\left(2\sqrt{x}+\dfrac{1}{3}\right)\left(2\sqrt{x}-\dfrac{1}{3}\right)\)
Bài 3:
\(x^2-2x+1=\left(x-1\right)^2\)
\(x^2-10x+25=\left(x-5\right)^2\)
\(x^2+x+\dfrac{1}{4}=\left(x+\dfrac{1}{2}\right)^2\)
\(\left(2x-3\right)\left(2x+3\right)=4x^2-9\)
\(\left(\dfrac{2}{3}x+5\right)\left(\dfrac{2}{3}x-5\right)=\dfrac{4}{9}x^2-25\)