srr mk làm nhầm
\(\dfrac{12}{x-3}=\dfrac{x-3}{3}\)
=> \(\left(x-3\right)^2=12.3\)
=> x-3=6 => x=9
hoặc x-3=-6 => x=-3
\(\dfrac{12}{x-3}=\dfrac{x-3}{3}\)
<=> \(12.3=\left(x-3\right)^2\)
=> \(\left(x-2\right)^3=36\)
=> \(\left(x-2\right)=6\)=> x=8
hoặc \(x-2=-6\) => x= -4
Giải:
\(\dfrac{12}{x-3}=\dfrac{x-3}{3}\)
\(\Rightarrow\left(x-3\right).\left(x-3\right)=12.3\)
\(\Rightarrow\left(x-3\right)^2=36\)
\(\Rightarrow\left(x-3\right)^2=6^2\) hoặc \(\left(x-3\right)^2=\left(-6\right)^2\)
\(x-3=6\) hoặc \(x-3=-6\)
\(x=9\) hoặc \(x=-3\)
Chúc bạn học tốt!
