\(\Leftrightarrow\left|\dfrac{1}{2}x-\dfrac{3}{2}\right|=\left|\dfrac{1}{3}x-\dfrac{5}{3}\right|\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-\dfrac{3}{2}=\dfrac{1}{3}x-\dfrac{5}{3}\\\dfrac{1}{2}x-\dfrac{3}{2}=-\dfrac{1}{3}x+\dfrac{5}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{6}x=-\dfrac{1}{6}\\\dfrac{5}{6}x=\dfrac{19}{6}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{19}{5}\end{matrix}\right.\)
Đúng 0
Bình luận (0)
