Tử số \(=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}\)
\(=\left(1+\frac{1}{100}\right)+\left(\frac{1}{2}+\frac{1}{99}\right)+...+\left(\frac{1}{50}+\frac{1}{51}\right)\)
\(=\frac{101}{1.100}+\frac{101}{2.99}+...+\frac{101}{50.51}\)
\(=101.\left(\frac{1}{1.100}+\frac{1}{2.99}+...+\frac{1}{50.51}\right)\)
Mẫu số \(=\frac{1}{1.100}+\frac{1}{2.99}+...+\frac{1}{99.2}+\frac{1}{100.1}\)
\(=2.\left(\frac{1}{1.100}+\frac{1}{2.99}+...+\frac{1}{50.51}\right)\)
=> phân số đề bài cho \(=\frac{101}{2}\)