10 + 1/12 × 100
= 10 + 25/3
= 30/3 + 25/3
= 55/3.
\(10+\frac{1}{12}\cdot100=100+\frac{25}{3}\)
\(=\frac{300}{3}+\frac{25}{3}\)
\(=\frac{325}{3}\)
\(10+\frac{1}{12}\times100=10+\frac{25}{3}=\frac{55}{3}\)
Mình sửa lại :
\(10+\frac{1}{12}\cdot100\)
\(=10+\frac{25}{3}\)
\(=\frac{30}{3}+\frac{25}{3}\)
\(=\frac{55}{3}\)
10 + \(\frac{1}{12}\)x 100
= 10 + \(\frac{25}{3}\)
= \(\frac{55}{3}\)