1. \(x+\sqrt{2x-3}\)\(=1+\sqrt{x-1}+\sqrt{x^2-3x+3}\)
2. \(\frac{\sqrt{x}}{1+\sqrt{1-x}}=x^2-2x+2\)
3. \(\sqrt[6]{6x-5}=\frac{x^7}{8x^2-10x+3}\)
4. \(\sqrt{x-3}+\sqrt{11-x}+\)\(6y+3\sqrt{4-2y^2}-15=0\)
5. \(\sqrt{2x-3}+\sqrt{21-2x}=\)\(x^4-12x^3+37x^2-12x+42\)
6. \(4x^2+2=3\sqrt[3]{4x^3+x}\)
giải pt vô tỉ. Ai giúp với tks tks tks <3
giải phương trình :
1, \(\sqrt{4-x^2}+2\sqrt[3]{x^4-4x^3+4x^2}=\left(x-1\right)^2+1-\left|x\right|\)
2, \(2x^3+9x^2-6x\left(1+2\sqrt{6x-1}\right)+2\sqrt{6x-1}+8=0\)
3, \(x^3-3x+1=\sqrt{8-3x^2}\)
4, \(\left(4x^2+x-1\right)\sqrt{x^2+x+2}=\left(4x^2+3x+5\right)\sqrt{x^2-1}\)
5, \(\sqrt[3]{3-x^3}=2x^3+x-3\)
6, \(\sqrt[3]{x^2+3x+3}+\sqrt[3]{2x^2+3x+2}=6x^2+12x+8\)
7, \(\frac{x^2+2x-8}{x^2-2x+3}=\left(x+1\right)\left(\sqrt{x+2}-2\right)\)
8, \(\frac{4x-1}{\sqrt{4x-3}}+\frac{11-2x}{\sqrt{5-x}}=\frac{15}{2}\)
9, \(x^2-4x+14+\sqrt{x+4}=2\sqrt{1+12x}+\sqrt{1+\sqrt{1+12x}}\)
a)Giải các phương trình sau bằng phương pháp đặt ẩn phụ:
1) \(x^2-3x-3=\frac{3\left(\sqrt[3]{x^3-4x^2+4}-1\right)}{1-x}\) ;2)\(1+\frac{2}{3}\sqrt{x-x^2}=\sqrt{x}+\sqrt{1-x}\)
b) Giải các phương trình sau(không giới hạn phương pháp):
1)\(2\left(1-x\right)\sqrt{x^2+2x-1}=x^2-2x-1\) ; 2)\(\sqrt{2x+4}-2\sqrt{2-x}=\frac{12x-8}{\sqrt{9x^2+16}}\)
3)\(\frac{3x^2+3x-1}{3x+1}=\sqrt{x^2+2x-1}\) ; 4) \(\frac{2x^3+3x^2+11x-8}{3x^2+4x+1}=\sqrt{\frac{10x-8}{x+1}}\)
5)\(13x-17+4\sqrt{x+1}=6\sqrt{x-2}\left(1+2\sqrt{x+1}\right)\);
6)\(x^2+8x+2\left(x+1\right)\sqrt{x+6}=6\sqrt{x+1}\left(\sqrt{x+6}+1\right)+9\)
7)\(x^2+9x+2+4\left(x+1\right)\sqrt{x+4}=\frac{5}{2}\sqrt{x+1}\left(2+\sqrt{x+4}\right)\)
8)\(8x^2-26x-2+5\sqrt{2x^4+5x^3+2x^2+7}\)
1)\(7\sqrt{3x-7}+\left(4x-7\right)\sqrt{7-x}=32\)
2)\(4x^2-11x+6=\left(x-1\right)\sqrt{2x^2-6x+6}\)
3)\(9+3\sqrt{x\left(3-2x\right)}=7\sqrt{x}+5\sqrt{3-2x}\)
4)\(\sqrt{2x^2+4x+7}=x^4+4x^3+3x^2-2x-7\)
5)\(\frac{6-2x}{\sqrt{5-x}}+\frac{6+2x}{\sqrt{5+x}}=\frac{8}{3}\)
6)\(2\left(5x-3\right)\sqrt{x+1}+\left(x+1\right)\sqrt{3-x}=3\left(5x+1\right)\)
7)\(\sqrt{7x+7}+\sqrt{7x-6}+2\sqrt{49x^2+7x-42}=181-14x\)
Giải các phương trình sau: (hệ phương trình)
1.\(\sqrt{3x^2+6x+7}+\sqrt{5x^2+10x+14}=4-2x-x^2\)
2.\(\sqrt{3-4x}+\sqrt{4x+1}=-16x^2-8x+1\)
3. \(\sqrt{x^2-2x+5}+\sqrt{x+1}=2\)
4. \(\left(-4x-1\right)\sqrt{x^2+1}=2x^2+2x+1\)
5. \(\sqrt{-4x-1}+\sqrt{4x^2+8x+3}=-4x^2-4x\)
6. \(\left(x-3\right)\left(x+1\right)+4\left(x-3\right)\sqrt{\frac{x+1}{x-3}}=-3\)
7. \(\sqrt{x\left(x-1\right)}+\sqrt{x\left(x+2\right)}=2\sqrt{x^2}\)
Ai làm được 4 bài hoặc nhiều hơn mik sẽ tick nha :)
Giải phương trình
1.\(\sqrt{2x-3}-\sqrt{5-2x}=3x^2-12x+14\)
2.\(x^2+2x+15=6\sqrt{4x+5}\)
3.\(x^2-5x-8=2\sqrt{x-2}\)
4.\(\sqrt{x+1+\sqrt{x+\frac{3}{4}}}=x+1\)
(Nghi binh 20/09)
Giải các phương trình sau:
a)\(32x^4-80x^3+50x^2+4x-3-4\sqrt{x-1}=0\)
b) \(\sqrt{5x^3-12x^2+12x-7}=\frac{x^2}{2}+2x-3\)
c)\(\sqrt{2x^2-16x+41}+\sqrt{3x^2-24x+64}=7\)
d)\(x+\sqrt{2x-3}=1+\sqrt{x-1}+\sqrt{x^2-3x+3}\)
e) \(\left(2x-1\right)\sqrt{x^2+1}=x^2+4x-5\)
f)\(\sqrt{8+\sqrt{x}}+\sqrt{5-\sqrt{x}}=5\)
g)\(2\left(x^2+2x+3\right)=5\sqrt{x^3+3x^2+3x+2}\)
h)\(\sqrt[3]{81x-8}=x^3-2x^2+\frac{4}{3}x-2\)
i)\(\sqrt{x\left(x+1\right)}+\sqrt{x\left(x+2\right)}=\sqrt{x\left(x-3\right)}\)
giải phương trình
a) \(\sqrt{2x-2\sqrt{2x-1}}-2\sqrt{2x+3-4\sqrt{2x-1}}+3\sqrt{2x+8-\sqrt{2x-1}}=4\)
b) \(4x^2+3x+3=4x\sqrt{x+3}+2\sqrt{2x-1}\)
c) \(\sqrt{x-4}+\sqrt{6-x}=x^2-11x+27\)
d) \(\sqrt{13x^2-6x+10}+\sqrt{5x^2-13x+\frac{17}{2}}+\sqrt{17x^2-48x+36}=\frac{1}{2}\left(36x-8x^2-21\right)\)
e) \(\sqrt{\frac{6}{3-x}}+\sqrt{\frac{8}{2-x}}=6\)
Giải phương trình vô tỉ:
a)\(\sqrt{\sqrt{3}-x}=x\sqrt{\sqrt{3}+x}\)
b)\(2\sqrt{x+3}=9x^2-x-4\)
c)\(2+3\sqrt[3]{9x^2\left(x+2\right)}=2x+3\sqrt[3]{3x\left(x+2\right)^2}\)
d)\(\sqrt{x-2+\sqrt{2x+5}}+\sqrt{x+2+3\sqrt{2x+5}}=7\sqrt{2}\)
e)\(\sqrt{4x+5}=2x^2-6x-1\)
f)\(\sqrt{5+\sqrt{x-1}}=6-x\)
g)\(x^2+2x\sqrt{x-\frac{1}{x}}=3x+1\)
Tìm ĐKXĐ giúp mik luôn nha!
\(\sqrt{4-\left(1-x\right)^2}-\sqrt{3}=0\)\(0\)
\(\sqrt{3x^2-5}=2\)
\(\sqrt{\frac{12x+5}{3}=2}\)
\(\sqrt{5x+3}=\sqrt{3-\sqrt{2}}\)
\(\sqrt{\left(\sqrt{x}-7\right)\left(\sqrt{x}+7\right)}=2\)
\(\sqrt{\frac{-6}{1+x}}=5\)
\(\sqrt{3x^2-4x+3}=1-2x\)
Mình cần lời giải cho những bài trên nha vì mình còn hơi khó hiểu trog dạng toán này. Tks nhiều nha
