ĐKXĐ:
1 - x² ≥ 0 và x - 1 ≥ 0
⇔ x² ≤ 1 và x ≥ 1
⇔ -1 ≤ x ≤ 1 và x ≥ 1
⇔ x = 1
Đúng 0
Bình luận (0)
Các câu hỏi tương tự
Giải các phương trình sau:1) 2 1 5 x 2) 2 1 5 x x 3) 3 1 2 x x 4) 3 2 2 x x5) 2 1 5 x x 6) 3 2 x x7) 2 3 2 1 x x 8) 2 1 4 1 0 x x 29) 2 5 4 3 1 1 23 2 3 1x xx x x x 10) 1 7 3 23 3 9x x xx x x 11) 5 296 2 1 3 116 4 4x xx x x 12) 2 412 1 2 1 2 1 2 1x xx x x x 13) 2 1 2 22 2xx x x x 14) 22 42 6 2 2 2 3
Đọc tiếp
Giải các phương trình sau:
1) 2 1 5 x 2) 2 1 5 x x
3) 3 1 2 x x 4) 3 2 2 x x
5) 2 1 5 x x 6) 3 2 x x
7) 2 3 2 1 x x 8) 2 1 4 1 0 x x 2
9) 2 5 4 3 1 1 2
3 2 3 1
x x
x x x x
10) 1 7 3 2
3 3 9
x x x
x x x
11) 5 296 2 1 3 1
16 4 4
x x
x x x
12)
2 4
1
2 1 2 1 2 1 2 1
x x
x x x x
13) 2 1 2 2
2 2
x
x x x x
14) 22 4
2 6 2 2 2 3
\(\frac{\left(x^2+x+1\right)\sqrt{x^2-x+1}+\left(x^2-x+1\right)\sqrt{x^2+x+1}}{\sqrt{x^2+x^2+1}}\div\frac{1}{\sqrt{x^2+1+x}-\sqrt{x^2-x+1}}\)
rút gọn biểu thức chứa căn thức bậc hai
√x/√x-1 - 6/√x-1 - 2√3/√x-1 (x>=0,xkhasc1 )
3-√x/√x-2 - 1-√x/√x-2 - -5√x/√x -2
2-6√x/√x-4 - 1-√x/√x-4 - 3-√x/√x-4
giải pt
a 2(x+3)(x-4)=(2x-1)(x+2)-27
b (3x+2)(x-1)-3(x+1)(x-2)=4
c (x+2)(x^2 -2x+4)-x(x-3)(x+3)=26
d (3x+2)(3x-2)-(3x-4)^2=28
e 5(x+3)^2-5(x-4)(x+8)=3x
f 2x(x+2)^2-8x^2=2(x-2)(x^2+2x+4)
g (2x-1)(4x^2+2x+1)-4x(2x^2-3)=23
h x(x-2)(x+2)-(x-3)(x^2+3x+9)+1=0
i x(x^2+x+1)-(x-1)(x+1)x=x^2+2
Rút gọn:
\(A=\frac{\left(x^2+x+1\right)\sqrt{x^2-x+1}+\left(x^2-x+1\right)\sqrt{x^2+x+1}}{\sqrt{x^4+x^2+1}}:\frac{1}{\sqrt{x^2+x+1}-\sqrt{x^2-x+1}}\)
Giải pt:
1) Căn(x^2 - x + 2) + 1 = căn(10 - x^2 + x)
2) 4căn(x) - 2 căn(2 - x) + x - 4 căn( 2x - x^2) + 1 =0
3) x^2 + 3x - 1= (x+2) căn(x^2 + x - 1)
4) 3x^2 + 4x + 2 = 3(x+2) căn(x^2 - 1)
Rút gọn biểu thức
1) x + 3 + sqrt{x^2-6x+9} (x le 3)
2) sqrt{x^2+4x+4}-sqrt{x^2} (-2 le x le 0)
3) sqrt{x^{2^{ }}+2sqrt{x^2-1}}-sqrt{x^2-2sqrt{x^2-1}}
4) dfrac{sqrt{x^2-2x+1}}{x-1} (x 1)
5) |x - 2| + dfrac{sqrt{x^2-4x+4}}{x-2} (x 2)
6) 2x - 1 - dfrac{sqrt{x^2-10x+25}}{x-5}
Đọc tiếp
Rút gọn biểu thức
1) x + 3 + \(\sqrt{x^2-6x+9}\) (x \(\le\) 3)
2) \(\sqrt{x^2+4x+4}-\sqrt{x^2}\) (-2 \(\le\) x \(\le\) 0)
3) \(\sqrt{x^{2^{ }}+2\sqrt{x^2-1}}-\sqrt{x^2-2\sqrt{x^2-1}}\)
4) \(\dfrac{\sqrt{x^2-2x+1}}{x-1}\) (x > 1)
5) |x - 2| + \(\dfrac{\sqrt{x^2-4x+4}}{x-2}\) (x < 2)
6) 2x - 1 - \(\dfrac{\sqrt{x^2-10x+25}}{x-5}\)
Bleft(frac{xsqrt{x}+x+sqrt{x}}{xsqrt{x}-1}-frac{sqrt{x}+3}{1-sqrt{x}}right).frac{x-1}{2x+sqrt{x}-1} ĐKXĐ: ...frac{left(xsqrt{x}+x+sqrt{x}right)left(1-sqrt{x}right)-left(sqrt{x}+3right)left(xsqrt{x}-1right)}{left(xsqrt{x}-1right)left(1-sqrt{x}right)}.frac{x-1}{2x+2sqrt{x}-sqrt{x}-1}frac{xsqrt{x}+x+sqrt{x}-x^2-xsqrt{x}-x-x^2+sqrt{x}-3xsqrt{x}+3}{left(xsqrt{x}-1right)left(1-sqrt{x}right)}.frac{x-1}{2sqrt{x}left(sqrt{x}+1right)-left(sqrt{x}+1right)}frac{-3xsqrt{x}+2sqrt{x}-2x^2+3}{left(xsqrt{x}-1ri...
Đọc tiếp
\(B=\left(\frac{x\sqrt{x}+x+\sqrt{x}}{x\sqrt{x}-1}-\frac{\sqrt{x}+3}{1-\sqrt{x}}\right).\frac{x-1}{2x+\sqrt{x}-1}\) ĐKXĐ: ...
\(=\frac{\left(x\sqrt{x}+x+\sqrt{x}\right)\left(1-\sqrt{x}\right)-\left(\sqrt{x}+3\right)\left(x\sqrt{x}-1\right)}{\left(x\sqrt{x}-1\right)\left(1-\sqrt{x}\right)}.\frac{x-1}{2x+2\sqrt{x}-\sqrt{x}-1}\)
\(=\frac{x\sqrt{x}+x+\sqrt{x}-x^2-x\sqrt{x}-x-x^2+\sqrt{x}-3x\sqrt{x}+3}{\left(x\sqrt{x}-1\right)\left(1-\sqrt{x}\right)}.\frac{x-1}{2\sqrt{x}\left(\sqrt{x}+1\right)-\left(\sqrt{x}+1\right)}\)
\(=\frac{-3x\sqrt{x}+2\sqrt{x}-2x^2+3}{\left(x\sqrt{x}-1\right)\left(1-\sqrt{x}\right)}.\frac{x-1}{\left(2\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)
\(=\frac{3-3x\sqrt{x}+2\sqrt{x}-2x^2}{\left(x\sqrt{x}-1\right)\left(1-\sqrt{x}\right)}.\frac{1}{\left(2\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)
\(=\frac{3\left(1-x\sqrt{x}\right)+2\sqrt{x}\left(1-x\sqrt{x}\right)}{\left(x\sqrt{x}-1\right)\left(1-\sqrt{x}\right)}.\frac{1}{\left(2\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)
\(=\frac{\left(2\sqrt{x}+3\right)\left(1-x\sqrt{x}\right)}{\left(x\sqrt{x}-1\right)\left(1-\sqrt{x}\right)}.\frac{x-1}{\left(2\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)
\(=\frac{-2\sqrt{x}-3}{1-\sqrt{x}}.\frac{x-1}{\left(2\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)
\(=\frac{-2\sqrt{x}-3}{1-\sqrt{x}}.\frac{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}{2\sqrt{x}-1}\)
\(=\frac{2\sqrt{x}+3}{2\sqrt{x}-1}\)
23 tháng 8 2021 lúc 19:43
Rút gọn:1) Pdfrac{x^2-sqrt{x}}{x+sqrt{x}+1}-dfrac{2x+sqrt{x}}{sqrt{x}}+dfrac{2left(x-1right)}{sqrt{x}-1}2)Aleft(dfrac{2sqrt{x}+x}{xsqrt{x}-1}-dfrac{1}{sqrt{x}-1}right):left(1-dfrac{sqrt{x}+2}{x+sqrt{x}+1}right)3) Aleft(dfrac{1}{sqrt{a}-1}-dfrac{1}{sqrt{a}}right):left(dfrac{sqrt{a}+1}{sqrt{a}-2}-dfrac{sqrt{a}+2}{sqrt{a}-1}right) 4) Aleft(dfrac{1}{sqrt{x}+1}-dfrac{2sqrt{x}-2}{xsqrt{x}-sqrt{x}+x-1}right):left(dfrac{1}{sqrt{x}-1}-dfrac{2}{x-1}right)Mng giúp e vs ạ, cần gấp :
Đọc tiếp
Rút gọn:
1) \(P=\dfrac{x^2-\sqrt{x}}{x+\sqrt{x}+1}-\dfrac{2x+\sqrt{x}}{\sqrt{x}}+\dfrac{2\left(x-1\right)}{\sqrt{x}-1}\)
2)\(A=\left(\dfrac{2\sqrt{x}+x}{x\sqrt{x}-1}-\dfrac{1}{\sqrt{x}-1}\right):\left(1-\dfrac{\sqrt{x}+2}{x+\sqrt{x}+1}\right)\)
3) \(A=\left(\dfrac{1}{\sqrt{a}-1}-\dfrac{1}{\sqrt{a}}\right):\left(\dfrac{\sqrt{a}+1}{\sqrt{a}-2}-\dfrac{\sqrt{a}+2}{\sqrt{a}-1}\right)\)
4) \(A=\left(\dfrac{1}{\sqrt{x}+1}-\dfrac{2\sqrt{x}-2}{x\sqrt{x}-\sqrt{x}+x-1}\right):\left(\dfrac{1}{\sqrt{x}-1}-\dfrac{2}{x-1}\right)\)
Mng giúp e vs ạ, cần gấp :<