Question

(1 - x)^2 - 1 = 16/3^2

Answer 1

\(\left(1-x\right)^2-1=\dfrac{16}{3^2}\)

\(\left(1-x\right)^2=\dfrac{16}{9}+1\)

\(\left(1-x\right)^2=\dfrac{25}{9}\)

\(\left(1-x\right)^2=\left(\dfrac{5}{3}\right)^2\) hoặc \(\left(1-x\right)^2=\left(\dfrac{-5}{3}\right)^2\)

\(\Rightarrow1-x=\dfrac{5}{3}\) hoặc \(1-x=\dfrac{-5}{3}\)

*) \(1-x=\dfrac{5}{3}\)

\(x=1-\dfrac{5}{3}\)

\(x=\dfrac{-2}{3}\)

*) \(1-x=\dfrac{-5}{3}\)

\(x=1+\dfrac{5}{3}\)

\(x=\dfrac{8}{3}\)

Vậy \(x=\dfrac{-2}{3}\); \(x=\dfrac{8}{3}\)