Question

1) Tim x:

\(\frac{1}{2}\cdot x+\frac{3}{5}\cdot x=\frac{-33}{10}\)

Answer 1

\(\frac{1}{2}x+\frac{3}{5}x=\frac{-33}{10}\)\(\Leftrightarrow\left(\frac{1}{2}+\frac{3}{5}\right)x=\frac{-33}{10}\)

\(\Leftrightarrow\frac{11}{10}x=\frac{-33}{10}\)\(\Leftrightarrow x=\frac{-33}{10}:\frac{11}{10}=\frac{-33}{10}.\frac{10}{11}=-3\)

Vậy \(x=-3\)

Answer 2

\(\frac{1}{2}\cdot x+\frac{3}{5}\cdot x=-\frac{33}{10}\)

\(\left(\frac{1}{2}+\frac{3}{5}\right)\cdot x=-\frac{33}{10}\)

\(\left(\frac{5}{10}+\frac{6}{10}\right)\cdot x=-\frac{33}{10}\)

\(\frac{11}{10}\cdot x=-\frac{33}{10}\)

\(x=-\frac{33}{10}:\frac{11}{10}=-\frac{33}{10}\cdot\frac{10}{11}\)

\(x=-\frac{33}{11}=-3\)

Answer 3

\(\frac{1}{2}\).x+\(\frac{3}{5}\).x=\(\frac{-33}{10}\)

(\(\frac{1}{2}\)+\(\frac{3}{5}\)).x=\(\frac{-33}{10}\)

(\(\frac{5}{10}\)+\(\frac{6}{10}\)).x=\(\frac{-33}{10}\)

\(\frac{11}{10}\).x=\(\frac{-33}{10}\)

x=\(\frac{-33}{10}\):\(\frac{11}{10}\)

x=-3

Answer 4

\(\frac{1}{2}\).   x  +\(\frac{3}{5}\). x = \(\frac{-33}{10}\)

 x.(\(\frac{1}{2}\)+      \(\frac{3}{5}\))=\(\frac{-33}{10}\)

x.\(\frac{11}{10}\)                 =\(\frac{-33}{10}\)

x                             =\(\frac{-33}{10}\) ÷      \(\frac{11}{10}\)

x                             = -3

Answer 5

\(\frac{1}{2}\cdot x+\frac{3}{5}\cdot x=-\frac{33}{10}\)

\(x\cdot\left(\frac{1}{2}+\frac{3}{5}\right)=-\frac{33}{10}\)

\(x\cdot\left(\frac{5}{10}+\frac{6}{10}\right)=-\frac{33}{10}\)

\(x\cdot\frac{11}{10}=-\frac{33}{10}\)

\(x=-\frac{33}{10}:\frac{11}{10}\)

\(x=-\frac{33}{10}\cdot\frac{10}{11}\)

\(x=-3\)

Vậy \(x=-3\)

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