a) \(\frac{x}{24}=\frac{6}{x}\)
\(\Leftrightarrow x^2=24.6\)
\(\Leftrightarrow x^2=144\)
\(\Leftrightarrow x=12\)
\(\frac{x}{24}=\frac{6}{x}\)
\(\Leftrightarrow x.x=6.24\)
\(\Leftrightarrow x^2=6.24\)
\(\Leftrightarrow x^2=144\)
\(\Leftrightarrow x=\pm12\)
1) Tìm x biết :
a) \(\frac{x}{24}=\frac{6}{x}\)
\(\Leftrightarrow x.x=24.6\)
\(\Rightarrow x^2=144\)
\(\Rightarrow x^2=12^2\)
\(\Rightarrow x=\pm12\)
b) \(2x+\frac{3}{24}=3x-\frac{1}{32}\)
\(\Rightarrow2x-3x=-\frac{3}{24}-\frac{1}{32}\)
\(\Rightarrow-x=-\frac{5}{32}\)
\(\Rightarrow x=\frac{5}{32}\)
\(\frac{x}{24}=\frac{6}{x}\)Theo công thức \(\frac{a}{b}=\frac{c}{d}\Rightarrow ad=bc\)
\(\Rightarrow x.x=24.6\Rightarrow x^2=144\)
Mà \(144=12^2\)
\(\Rightarrow x=12\)
a) \(\frac{x}{24}=\frac{6}{x}\Leftrightarrow2x=144\Leftrightarrow x=72\)
b) \(2x+\frac{3}{24}=3x-\frac{1}{32}\)
\(\Leftrightarrow5x=\frac{5}{32}\)
\(\Leftrightarrow x=\frac{1}{32}\)
Vậy....