\(3⋮2n-1\)
\(\Rightarrow2n-1\inƯ\left(3\right)=\left\{\pm1;\pm3\right\}\)
bn tự lập bảng nha !
\(\Rightarrow2n-1\inƯ\left(3\right)\)
\(\Rightarrow2n-1\in\left\{1;-1;3;-3\right\}\)
\(\Rightarrow2n\in\left\{2;0;4;-4\right\}\)
\(\Rightarrow n\in\left\{1;0;2;-2\right\}\)
học tốt
\(3⋮2n-1\)
\(\Rightarrow2n-1\inƯ\left(3\right)\)
\(\Rightarrow2n-1\in\left\{\pm1;\pm3\right\}\)
3 ⋮ 2n − 1
⇒2n − 1 ∈ Ư( 3) ={ ±1; ± 3 }
⇒2n ∈ {2;0;4; − 4}
⇒n ∈ {1;0;2; − 2}
Vậy n ∈ {1;0;2; − 2}
Bài giải
\(3⋮2n-1\)
\(\Rightarrow2n-1\inƯ\left(3\right)\)
\(\Rightarrow2n-1\in\hept{\pm1;\pm3}\)
\(3⋮2n-1\)
\(\Rightarrow2n-1\inƯ\left(3\right)=\left\{\pm1;\pm3\right\}\)
\(\Rightarrow2n-1=1;-1;3;-3\)
\(\Rightarrow2n=2;0;4;-2\)
\(\Rightarrow n=1;0;2;-1\)
t.i.k.mk với
