Question

1: (a-3)√b^2/a^2-6*a+9 (a>3)

2: 1/3+a* √a^2+6a+9/b^2

3:√(a+1)^2 - 3a/a-2 * √a^2-4a+4/9 (a>2)

4: (3-√3)*(-2√3)+(3√3+1)^2

5: (2√3-3√2)^2 + √(12√6-5)^2

6: (4+√15)*(√10-√6)*√4-√15

7: √3-√5 * (√10 -√2)*(3+√5)

Mọi người giúp mk với

Answer 1

đề bài khó hỉu quá

Answer 2

1: \(=\left(a-3\right)\cdot\dfrac{\left|b\right|}{a-3}=\left|b\right|\)

2: \(\dfrac{1}{3+a}\cdot\sqrt{\dfrac{a^2+6a+9}{b^2}}\)

\(=\dfrac{1}{a+3}\cdot\dfrac{\left|a+3\right|}{b}=\pm\dfrac{1}{b}\)

3: \(=\left|a+1\right|-\dfrac{3a}{a-2}\cdot\dfrac{\left|a-2\right|}{3}\)

\(=\left|a+1\right|-a\)

4: \(=-6\sqrt{3}+6+28+6\sqrt{3}=34\)