Đặt a=2015/2017
\(A=1-a+a^2-a^3+...+a^{2018}\)
=>\(a\cdot A=a-a^2+a^3-a^4+...+a^{2019}\)
=>\(A\cdot\left(a+1\right)=a^{2019}+1\)
=>\(A=\dfrac{a^{2019}+1}{a+1}\)
Tính :A= [(2018/1)+(2017/2)+(2016/3)+(2015/4)+...+(4/2015)+(3/2016)+(2/2017)+(1/2018)]/[(2019/1)+(2019/2)+(2019/3)+(2019/4)+...+(2019/2015)+(2019/2016)+(2019/2017)+(2019/2018)+(2019/2019)]
Tính :A= [(2018/1)+(2017/2)+(2016/3)+(2015/4)+...+(4/2015)+(3/2016)+(2/2017)+(1/2018)]/[(2019/2)+(2019/3)+(2019/4)+(2019/5)+...+(2019/2015)+(2019/2016)+(2019/2017)+(2019/2018)+(2019/2019)]
Tính:
A=2019/2018 - 2018/2017 + 2017/2016 - 2016/2015
B=1/2019 - 1/2018 + 1/2017 - 1/2016
C=1/2017 - 1/2016 + 1/2015 - 1/2014
2016.(\(\frac{1}{2015}-\frac{2017}{2018}\))-2017.\(\left(\frac{1}{2015}-2\right)\)
Tìm x,biết:
x+2015/5 + x+2014/6 = x+2017/3 + x+2018/2
Hướng dẫn: x+2015/5+1 + x+2014/6+1 = x+2017/3+1 + x+2018/2+1
1010/2*1011/2*1013/2*....*2017/2*2018/8 : 1*3*5*....*2015*2017
Cho x,y>0 thỏa mãn
x^2015+y^2015=x^2016+y^2016=x^2017+y^2017
C/m: 1/x^2018+1/y^2018=1/x^2019+1/y^2019
(1/2+2015/2016+2016/2017+1)(2015/2016+2016/2017+7/22)
thục hiện phép tính: (1/2+1/3+1/4+.....+1/2017+1/2018)/(2017/1+2016/2+2015/3+.....+2/2016+1/2017)
Các bạn giúp mình nha ! Thank you very much :)
