\(f\left(1\right)=\dfrac{3.1^2-5}{1+2}=-\dfrac{2}{3}\)
\(\lim\limits_{x\rightarrow1}f\left(x\right)=\lim\limits_{x\rightarrow1}\dfrac{3x^2-5}{x+2}=\dfrac{3.1^2-5}{1+2}=-\dfrac{2}{3}\)
\(\Rightarrow f\left(1\right)=\lim\limits_{x\rightarrow1}f\left(x\right)=-\dfrac{2}{3}\)
\(\Rightarrow\) Hàm số \(f\left(x\right)\) liên tục tại \(x=1\)