Ta có: \(n_{\left(CH_3COO\right)_2Mg}=\dfrac{0,71}{142}=0,005\left(mol\right)\)
PT: \(2CH_3COOH+Mg\rightarrow\left(CH_3COO\right)_2Mg+H_2\)
__________0,01_______________0,005______0,005 (mol)
a, \(C_{M_{CH_3COOH}}=\dfrac{0,01}{0,025}=0,4\left(M\right)\)
\(V_{H_2}=0,005.22,4=0,112\left(l\right)\)
b, \(CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O\)
\(n_{NaOH}=n_{CH_3COOH}=0,01\left(mol\right)\)
\(\Rightarrow V_{NaOH}=\dfrac{0,01}{0,75}=\dfrac{1}{75}\left(l\right)=13,33\left(ml\right)\)
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