Câu 4:
\(a,CaCO_3+2CH_3COOH\rightarrow\left(CH_3COO\right)_2Ca+CO_2+H_2O\\ n_{CH_3COOH}=0,2.1=0,2\left(mol\right)\\ b,n_{CaCO_3}=n_{\left(CH_3COO\right)_2Ca}=\dfrac{0,2}{2}=0,1\left(mol\right)\\ m_{CaCO_3}=0,1.100=10\left(g\right)\\ c,m_{muối}=m_{\left(CH_3COO\right)_2Ca}=158.0,1=15,8\left(g\right)\)