\(1.a.CTHH:M_2O_3\\ 4M+3O_2\xrightarrow[]{t^0}2M_2O_3\\ \Rightarrow n_M:4=n_{M_2O_3}:2\\ \Rightarrow\dfrac{2,7}{M}:4=\dfrac{5,1}{2M+48}:2\\ \Rightarrow M=27,Al\\ \Rightarrow CTHH:Al_2O_3\\ bAl_2O_3:Alumium.oxide\\ 2.KL:R\\ R+2HCl\rightarrow RCl_2+H_2\\ n_R=\dfrac{1}{2}n_{HCl}=0,1mol\\ M_R=\dfrac{2,4}{0,1}=24\\ M.là.Mg\)