Question

Answer 1

Câu 40 : 

\(Zn+H_2SO_4\rightarrow ZnSO_4+H_2\)

 Ta có : \(n_{H2}=n_{Zn}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)

\(m_{Zn}=0,15.65=9,75\left(g\right)\)

\(m_{Cu}=15,75-9,75=6\left(g\right)\)

2) \(n_{Zn}=n_{ZnCl2}=0,15\left(mol\right)\Rightarrow m_{ZnCl2}=0,15.136=20,4\left(g\right)\)