Ta có: \(n_{H_2SO_4}=0,1.0,1=0,01\left(mol\right)\)
PT: \(H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O\)
a, Theo PT: \(n_{NaOH}=2n_{H_2SO_4}=0,02\left(mol\right)\)
\(\Rightarrow V_{NaOH}=\dfrac{0,02}{0,1}=0,2\left(l\right)\)
b, \(n_{Na_2SO_4}=n_{H_2SO_4}=0,01\left(mol\right)\)
\(\Rightarrow C_{M_{Na_2SO_4}}=\dfrac{0,01}{0,1+0,2}=\dfrac{1}{30}\left(M\right)\)
c, \(H_2SO_4+Ba\left(OH\right)_2\rightarrow BaSO_4+2H_2O\)
Theo PT: \(n_{BaSO_4}=n_{H_2SO_4}=0,01\left(mol\right)\)
\(\Rightarrow m_{BaSO_4}=0,01.233=2,33\left(g\right)\)