\(89.\\ Cu\left(OH\right)_2\xrightarrow[]{t^0}CuO+H_2O\\ H_2SO_4+CuO\xrightarrow[]{}CuSO_4+H_2O\\ n_{Cu\left(OH\right)_2}=n_{CuO}=n_{H_2SO_4}=0,02mol\\ m_{Cu\left(OH\right)_2}=0,02.98=1,96\left(g\right)\\ \Rightarrow C\)
\(90.\\ n_{Na}=\dfrac{0,23}{23}=0,01\left(mol\right)\\ 2Na+2H_2O\rightarrow2NaOH+H_2\\ n_{H_2}=0,01:2=0,005\left(mol\right)\\ V_{H_2}=0,005.22,4=0,112\left(l\right)\\ \Rightarrow A\\ n_{NaOH}=n_{Na}=0,01mol\\ C_{M_{NaOH}}=\dfrac{0,01}{0,05}=0,2M\\ \Rightarrow B\)
\(91.\\ HCl+NaOH\xrightarrow[]{}NaCl+H_2O\\ n_{HCl}=n_{NaOH}=0,2mol\\ V_{HCl}=\dfrac{0,2}{0,1}=2\left(l\right)\\ \Rightarrow B\)
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