Question

Answer 1

\(a,\)\(N=\dfrac{2L}{3,4}=3000\left(nu\right)\)

\(b,\)Theo NTBS và NTBS ta có: \(\left\{{}\begin{matrix}X-A=350\\X+A=1500\end{matrix}\right.\rightarrow\left\{{}\begin{matrix}X=925\left(nu\right)\\A=575\left(nu\right)\end{matrix}\right.\)

Answer 2

\(a,\)\(N=\dfrac{2L}{3,4}=3000\left(nu\right)\)

\(b,\)Theo NTBS và NTBS ta có: \(\left\{{}\begin{matrix}X-A=350\\X+A=1500\end{matrix}\right.\rightarrow\left\{{}\begin{matrix}X=925\left(nu\right)\\A=575\left(nu\right)\end{matrix}\right.\)