Câu 4 :
PTHH : 4P + 5O2 ---to---> 2P2O5
PTHH : P2O5 + 3H2O -> 2H3PO4
Vậy X là H3PO4
\(\Rightarrow\) PTHH : H3PO4 + 3KOH -> K3PO4 + 3H2O
0,5 \(\dfrac{0.5}{3}\)
\(m_{K_3PO_4}=\dfrac{0.5}{3}.212=\dfrac{106}{3}\left(g\right)\)
\(\Rightarrow m=\dfrac{106}{3}:\dfrac{193}{31}=\dfrac{3286}{579}\left(g\right)\)