Bài 3 :
\(n_{H2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\)
a) Pt : \(Zn+H_2SO_4\rightarrow ZnSO_4+H_2|\)
0,1 0,1 0,1
b) \(m_{Zn}=0,1.65=6,5\left(g\right)\)
c) \(m_{ZnSO4}=0,1.161=16,1\left(g\right)\)
\(m_{ddspu}=6,5+100-\left(0,1.2\right)=106,3\left(g\right)\)
\(C\%_{ZnCl2}=\dfrac{16,1.100}{106,3}=15,15\%\)
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